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IV math for Pharmacy Tech Test

by Cliff
(Texas)

A patient is receiving an infusion that started at 1400 hours. The bag used contained 500mL of 0.25% active drug in 0.9% NaCl. The infusion pump was set to deliver 75mL/Hr. The surgeon ordered that the infusion run until the patient receive 750mg of the active drug. What time will the infusion be terminated?
A. 5:00 P.M.
B. 7:00 P.M.
C. 10:00 P.M.
D. 12:00 A.M.

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Infusion question
by: Brad Wojcik, Pharm D

I come up with 6 pm.
750 mg/(100 ml/0.25 g)(1 g/1000 mg)(1 H/75 mL) = 4 h

1400 h + 4 h = 1800 h or 6 pm.

Note that I change 0.25% to 0.25g/100 mL.
0.25% w/v is the same as 0.25% g/mL. Dividing by 100% to remove the % we get 0.25g/100 mL.
Confusing
by: HY

I thought it is 6pm also, but how come the answer is not there?
Unsure
by: Anonymous

I got 10 pm.
I'm not sure if that right or not.
I multiplied to get total amount of mg in the bag then subtracted from the total desired (750) then, used the rate to determine that it would take 8 hours to get to 750 and since 2pm is 1400 then 8 hrs later would be 10pm

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